MEMMOVE(3) | Linux Programmer's Manual | MEMMOVE(3) |
NAME
memmove - copy memory areaSYNOPSIS
#include<string.h>
void *memmove(void * dest , const void * src , size_t n );
DESCRIPTION
The memmove() function copies n bytes from memory area src to memory area dest. The memory areas may overlap: copying takes place as though the bytes in src are first copied into a temporary array that does not overlap src or dest, and the bytes are then copied from the temporary array to dest.RETURN VALUE
The memmove() function returns a pointer to dest.CONFORMING TO
SVr4, 4.3BSD, C89, C99, POSIX.1-2001.SEE ALSO
bcopy(3), memccpy(3), memcpy(3), strcpy(3), strncpy(3), wmemmove(3)COLOPHON
This page is part of release 3.53 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://www.kernel.org/doc/man-pages/.1993-04-10 | GNU |